|
各位先進們,老師最近派了一個鍵盤掃描題目給我們寫,硬體架構和老師發的一些資料都在附件中,我有寫出來兩個程式,一個是用Mealy狀態機防彈跳和看書說故事的寫法,不過我很討厭Mealy狀態機和看書說故事,所以我又寫了第二個寫法,用旗標交握以及計數器防彈跳,因為班上沒人寫出來,所以才在這裡發帖,主要想看先進們的邏輯寫法,以下是我的程式,寫的邏輯很爛可以噹我沒關係,呵呵...因為小弟弟剛升會員,所以只有1RDB,希望先進們見諒.* ^! m! C! D9 R7 b5 p6 Q5 R. Z
, M) H# N! u5 |& ?$ X
Library ieee;
3 M; X* n7 ]! ]. l% C4 h, oUse ieee.std_logic_1164.all;# v8 l( h+ ~$ l& w3 ^' F
Use ieee.std_logic_unsigned.all;
/ l; A/ V. C, e/ [9 h. O4 b! |& g, b- T, _0 c1 h
Entity Keyboard_scanning_2 is% q9 L v; i4 ?( G8 A4 ^0 X1 s3 V
Port(3 E1 T: z; f% M, Y: k& S
clk,c1,c2,p_21 : in std_logic;) l. g: o& U n8 ]' ^3 v
kbi : in std_logic_vector(2 downto 0);% X' z: D9 {9 E* |; Z, I. n; Q
lt,p_20,p_6 : out std_logic;
8 J* [& @' i( ^/ _( T kscano,key : out std_logic_vector(3 downto 0));
3 x. V+ R9 B' {: x4 M3 U7 W, I: Uend Keyboard_scanning_2;
7 x6 }$ Z& n6 z1 n$ C6 s) x
1 O6 g6 t& `: M) N5 mArchitecture K_S of Keyboard_scanning_2 is
$ ~, }8 u0 L5 e! r4 U; L2 ]2 R& Gsignal x0,x1,x2,x3,ena,l_p,d_b,count : std_logic;
/ I. K& O$ ?8 I/ ~- S# O0 ]* ssignal D : std_logic_vector(1 downto 0);/ T. u% P! u9 u: [2 _- M
signal ks1,kok : boolean;
0 c% h3 U ^ \, `; `$ UBegin
n& D& @+ l( M9 L0 dlt<=c1 nor c2;( ]6 o* m5 d+ ?
8 O. y) f0 k/ }$ C( _freqprocess(clk)
& Y) D8 e ?3 V/ H# V- t; I. @1 ~' [3 h2 ovariable ff : std_logic_vector(16 downto 0); # x. p N, K$ O b9 s3 v) [. a1 A
Begin
' q& d* [$ W' X+ \' D& u if (clk'event and clk='1') then% \) Q/ B, }# e6 o
ff:=ff+1;/ b: z- a2 U/ N* O) k R/ a
end if;
: M1 Q9 S7 M0 E& i l_p<=ff(12);
- T: m6 c1 a- _7 z) Y' u d_b<=ff(13);
: E' [$ C" P, U$ u. k count<=ff(15);
3 r' d3 G- Z6 ?& tend process freqp;4 e2 b# f) c- _# A1 ^6 e5 g/ O
% b* a3 ^: V% |4 L% Y9 a3 i% e% ^% k5 wdebrocess(d_b)
1 y8 s; O2 Y6 tvariable c : std_logic_vector(1 downto 0);
6 J( F6 |8 d+ ~2 OBegin2 d( B2 r/ F3 h7 n0 v/ _7 ]
if (d_b'event and d_b='1') then
. s* l; v3 t* e$ }6 |6 V3 Z4 i if (kbi(2) or kbi(1)or kbi(0))='1' then
! y- R! x! K3 O1 b% c if c="11" then
% n$ z0 q5 ]" V$ g# Z# ` ena<='1';
/ S- O, K6 U0 N6 s G9 Q0 Y x2<=kbi(1); g+ z! u0 g5 m6 x
x3<=kbi(0);
% ^: c5 u; D! \0 I: } kok<=false;, a" G* q7 R3 b7 J) E- o3 x# V! ?
else + O0 m# @3 K$ m8 H0 Y. _
c:=c+1;
2 p2 E! I# o" `9 z% A8 e1 ? end if;
1 E) ~6 y" E- `& L elsif (kbi(2) or kbi(1)or kbi(0))='0' then
# N, ?* b3 X2 Z0 n% z ena<='0';& S A- h) ^$ R! {) b+ A& \* j/ t+ v5 Q
kok<=true;) f+ \5 V. A) Q. A8 ]. y* t' u# o
c:="00";
: P$ K( U) T& O7 ]; R( Y8 R. m/ e' s end if; + B' J! d4 H* Y2 A+ G0 |
end if;
# @) d8 j7 u5 {4 t# R" v g: gend process deb;
+ J) V) d6 C9 b( `7 H5 S% f) V* t* i. V) @* Q: f0 s2 v
counter_scanrocess(count)6 I( @' L0 g6 C. U7 t
Begin J" x( [( S9 m* }% h7 b
if (count'event and count='1') then
7 ~4 [* [) s# U) {: h$ W& Y9 n3 H if ena='1' then! v% m* G) N7 t
x1<=D(1);
% I) N( B- v0 z4 ]6 ` x0<=D(0);
# C6 d2 z3 _0 N else& [( _1 B) j! w# i' K! U
if D="11" then
- d# ]9 e/ J# J8 o: \ u/ Z D<="00";
/ w0 k; x, ?$ b4 d* \0 P& B: ~4 l else
: d+ b( Q$ E/ s9 q9 L! R5 Y& X D<=D+1;# B9 ^4 R- l7 Y/ ^8 V0 q
end if;
) Y$ c" P" `% h2 ?$ X) w; X$ { end if;
! X; ]' V2 @; D end if;$ }, m$ x( ^( s- o9 |- c
case D is
6 s5 `6 t9 Q* K! Z/ A$ y. [! @: e1 S2 Z when "00"=>
C' ^: K7 |# h1 `! B; _ kscano<="0001";& J) J* n6 T% X' ^
when "01"=>% I& G. t3 ~2 k( ?* p
kscano<="0010";
p( n' U! N u when "10"=>- ^) J q2 L. @# B, m6 T
kscano<="0100"; # k$ s0 t" |1 h$ ?; n* P$ R
when "11"=>
6 I; O. l6 B5 W* x kscano<="1000";0 K( U* n2 O! X1 @* P7 ]
when others=>null;
# R& _2 k. D; f* G8 s end case;
: n4 _1 e }9 W' [& ?* v: u, Eend process counter_scan; T/ B0 q/ L% I+ u
+ |) s0 s& s" B# k+ lld_plsrocess(l_p)
' d6 W! U$ L3 ]Begin
3 ?3 c5 T1 c- i, M if (l_p'event and l_p='1') then, u4 k+ I8 L! Z/ L
if ena='1' then
' N$ b$ o$ E8 b9 B0 @5 B5 g if ks1 then
0 b' V+ X. [3 `' z p_6<='1';
+ [+ R) c( A" _ r, W: N$ N H p_20<='0';
8 D- n8 W& [: L) Y5 B) n2 b& p ks1<=false;
, `6 |0 R6 {% D# l) I! v! A elsif ks1=false then6 Y# ~* _( n, P# S
p_6<='0'; , Y+ t1 n( R3 g
if p_21='1' then6 j! `8 ^: q6 K, ~8 {8 w+ [
p_20<='1';
% w' L" }9 |# Q! q& {. u# i0 n& j' ~ key(3)<=x3;
$ a: O0 c$ T& f& i4 p- O key(2)<=x2;
2 s: u7 K) n6 _ key(1)<=x1;5 p/ Q& R* ]3 h& ^9 x5 u; j% \* ]
key(0)<=x0;
# ?3 l9 ], {5 X9 O* i: ^ else
, i% t3 l6 s& F( w p_20<='0';7 a5 e/ A2 {* n: J; T
end if;
' U$ V3 M( m5 @( D) p end if;
) S9 o" ]7 r3 g elsif kok then/ H2 k/ }' ^7 M* c$ b
ks1<=true; ) ^ s+ e" c5 ~7 W" ]/ Q! L* G2 `
end if;
; h; j) S8 ]$ O$ O, f1 k1 L end if;; s" E- h1 O5 y" d* u4 w- S
end process ld_pls;
4 g' ?% ~- @( P. D+ ?- pend K_S; |
評分
-
查看全部評分
|