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貢獻code-matlab amp
好像不錯 下再看看
2 E9 F; G# F0 d0 R, A- B/ hs = tf('s');. X6 C m0 |# T5 E& o2 B) M
R1=2e3 j6 A1 d$ A" @/ z
C1 =0.47e-9
2 G3 d8 O& ?0 I. M! qR2 =8.2618e+0034 _: K* A! F T. F$ \
R3 =500' e# @/ m& s0 b* B+ M
Z1=R3+(R1/(1+s*C1*R1)), B! T; G. ~& ?1 k0 a7 Z9 y% Z1 B
Z2=R2
' W* f; Q5 K1 u5 Z% OPA gain:A;OPA open loop gain:A0 ; dominant pole ; compensator close feedback gain:Gcl ( ~: q- G( U8 _" E x3 m
A0=10.77 J1 h; p; W$ I
p=5e32 Z1 A+ I3 R" S; V" R/ l. A' m1 z
A=A0*p/(s+p)0 Y- O( y4 c6 T8 u0 U3 ~" J
figure(1)$ ]3 T, F& P! J. x# c( p* M ]
margin(A)' h; o$ ? z* l7 u5 M5 w. \$ |
Gc=-((Z2/Z1)/(1+((1+(Z2/Z1))/A)))
" z5 s# o' A1 J0 q! Hfigure(2)' Z( P/ V8 G1 {/ k8 j" [. _3 m: c
margin(Gc) |
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