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各位先進們,老師最近派了一個鍵盤掃描題目給我們寫,硬體架構和老師發的一些資料都在附件中,我有寫出來兩個程式,一個是用Mealy狀態機防彈跳和看書說故事的寫法,不過我很討厭Mealy狀態機和看書說故事,所以我又寫了第二個寫法,用旗標交握以及計數器防彈跳,因為班上沒人寫出來,所以才在這裡發帖,主要想看先進們的邏輯寫法,以下是我的程式,寫的邏輯很爛可以噹我沒關係,呵呵...因為小弟弟剛升會員,所以只有1RDB,希望先進們見諒.
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) ~' D; a7 g) G) V) B: X% RLibrary ieee;
' k- k. |! N. K6 I: q, d& `Use ieee.std_logic_1164.all;; M8 J/ P; f5 ^) ?; b3 y9 Q0 M4 y
Use ieee.std_logic_unsigned.all; d0 m3 o1 A% v+ o9 F$ K7 f
! a- {" W; i+ u# D. m) EEntity Keyboard_scanning_2 is1 m+ c; O! T8 \; i2 z; Z
Port(: P1 V1 B/ s+ q6 e
clk,c1,c2,p_21 : in std_logic;3 P1 U) J! z# \( L. y
kbi : in std_logic_vector(2 downto 0);4 j5 w1 j: V( [! u
lt,p_20,p_6 : out std_logic;& C8 I6 B' D5 j& w$ G6 j. ~
kscano,key : out std_logic_vector(3 downto 0));
1 H# g2 n" @8 K; xend Keyboard_scanning_2;: Q" A2 D5 E$ V7 @; t
% @. ~% G8 F9 W& z& { X" X* ~- B4 F
Architecture K_S of Keyboard_scanning_2 is
- R" Q8 y3 H2 z) D. Osignal x0,x1,x2,x3,ena,l_p,d_b,count : std_logic;
6 O! {0 R, j$ ~1 Dsignal D : std_logic_vector(1 downto 0);& q4 i: I& l! n. s
signal ks1,kok : boolean;
, m) X3 P5 ^& Y: w1 U6 kBegin' U# j8 A$ l2 o0 G
lt<=c1 nor c2;
* d9 s( K5 d4 [9 I2 Q M: E7 W- x0 d3 Z
freqprocess(clk)
# H4 |1 f5 k3 d; K% pvariable ff : std_logic_vector(16 downto 0);
+ Y" l' L2 U- tBegin; \, c- L; Z. r# o& T) e8 h
if (clk'event and clk='1') then8 ^: |, _) O5 k" _; g
ff:=ff+1;
+ v# z, C8 X& c8 ^- l3 H end if;
1 `3 G8 A* u+ @ l_p<=ff(12); ! M0 q" y1 U+ M9 h/ \5 Y: |$ k
d_b<=ff(13);
% r/ z0 R6 R7 R- {2 s7 G count<=ff(15); 9 N$ v; i8 Z2 _. [8 @
end process freqp;: s* o% Y2 u2 \" o& \$ `, p
" M0 j2 E2 z4 F) M; G) a7 q6 M0 w& Sdebrocess(d_b)
% Z0 ]! t- m! m& q3 N# Nvariable c : std_logic_vector(1 downto 0);
1 n( R P0 \& E7 L: X( V7 H5 |3 V rBegin
' z0 o* {4 j( h# H- l% w if (d_b'event and d_b='1') then
1 w0 @8 H. Y+ K' p+ ?( O if (kbi(2) or kbi(1)or kbi(0))='1' then
9 h1 o6 B7 k/ t3 v5 ]" `2 u6 u2 D) \ if c="11" then
. c$ `4 U. S& g" v Z' H9 Q ena<='1';
4 m1 H0 k. H5 ~. X x2<=kbi(1);
+ h, |" x0 x U8 X, j4 G8 p1 l x3<=kbi(0);
r7 g+ U; m" I4 d6 ?; }. a. W kok<=false;
& z- y; ]4 |3 K! L7 H3 P else
' O$ t7 q; e* S! R- { c:=c+1;
' ?) t r' l' | end if;
g+ k, n( ?5 W& n, Z! P elsif (kbi(2) or kbi(1)or kbi(0))='0' then% @- ?$ m; i+ I" c
ena<='0';
* c$ q* Q* ?; _) S' v0 w kok<=true;
( v8 \' O* }1 A; g) W. [1 U& P9 D c:="00"; 2 h/ T- R" ]3 z. G2 L% R9 L) B6 ?
end if; 6 ~1 r* \( h" C8 ]( l$ q$ a
end if;# r+ {3 e$ X# G8 k+ n
end process deb;2 T% ~! l' R. i8 O0 h
" I6 M7 b! r% C1 A% t: X) scounter_scanrocess(count)
! y' ^2 P0 `0 |& h2 K: C( V l8 kBegin
. t- j6 W2 D6 a: O! C5 Y if (count'event and count='1') then4 ?5 s% I2 H* O# b8 z( _+ Q
if ena='1' then
4 u2 ]8 @0 p: L) k' ~: Q x1<=D(1);- F8 f- L& K5 N' q5 C6 T9 f
x0<=D(0);
* o+ Q/ ]: s- {- ~7 Y% z! A% F else
) f. y. T& _7 o if D="11" then& Z1 o) h0 ^2 J7 x4 d, i. Z2 f. _
D<="00";
. R U* n* y: R# C8 g% P else
; { H: ^3 E1 }1 G D<=D+1;- f3 S7 ~4 L0 h j2 K8 ]
end if;- j' D8 S# w/ f2 E& I1 H2 S: k8 y
end if;
6 K% W) R' W$ L" p; I end if;' l! S7 a5 }/ j4 H6 v; v
case D is8 C% {* j8 \5 x! D2 F9 m
when "00"=>
' E8 U8 V4 i9 N" A5 ~ kscano<="0001";
/ A+ J2 J3 [. t8 [* |5 l8 h! U7 {. h when "01"=>
# L* x/ E+ W: u. Z$ o7 y* x# J& B kscano<="0010"; ! V4 K6 X7 K/ U" c0 y( m
when "10"=>
/ m) G t0 K) r I& u; R1 C# B kscano<="0100";
8 c0 T- `2 {6 c8 F& H) ~ when "11"=>8 _* a0 h* U Z2 l' e) _) C
kscano<="1000";
3 _% |; S5 i, {7 W5 g& s7 Z4 b u/ B when others=>null;+ R7 k R" W v# h2 W7 A2 s
end case; 9 u' u7 R+ f1 G) @% L: J" I
end process counter_scan;
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ld_plsrocess(l_p)
8 c, c9 I* h3 NBegin0 d3 N0 M* Y: q% O. V2 s7 m3 b
if (l_p'event and l_p='1') then a) A: \/ ?+ Y$ U5 Y( f
if ena='1' then5 R& i* w# u: m" v9 s7 D/ H+ i, J
if ks1 then
+ w& G' H& b1 }3 a1 o/ Y p_6<='1';$ O7 G% k" J- z T
p_20<='0';
* }( m( u7 ^" ?! s# W* m ks1<=false;6 [3 n( V7 }, U" e! P3 h
elsif ks1=false then4 C3 R( T+ a5 J8 U! H W) e
p_6<='0'; + b: t" |- v3 |& [2 U* A& P( U% F. i
if p_21='1' then5 r9 z& Y$ [: ~8 j$ M# a
p_20<='1';; }8 I5 x7 k. p( f
key(3)<=x3;4 A/ S7 ^2 U8 w, i8 u; r
key(2)<=x2;- y: T Y5 ~( n) e
key(1)<=x1;
" s! l, W' {9 j& P! J) L key(0)<=x0;$ e$ A, T% Z1 t) e# W6 e8 z
else5 [% F k l# k5 @
p_20<='0';* q6 G3 ?3 t' ^0 d4 i* I
end if;9 U) @8 N' C0 f% ^4 U+ I% ^4 P" z( B
end if;' j! Q P- ~4 p9 l' v' c
elsif kok then6 B4 C8 Q' M% z" z
ks1<=true;
6 b. B2 I1 @8 o: P" t end if;
7 U6 B8 ?, B- _0 |* a% n end if;
3 H5 T3 `- V, \end process ld_pls;
9 F/ \& e8 o# ]. rend K_S; |
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