Chip123 科技應用創新平台

 找回密碼
 申請會員

QQ登錄

只需一步,快速開始

Login

用FB帳號登入

搜索
1 2 3 4
查看: 6419|回復: 7
打印 上一主題 下一主題

[問題求助] 靜電放電測試

[複製鏈接]
1#
發表於 2008-5-21 12:14:35 | 顯示全部樓層
For ESD test (HBM)
! i1 t7 T, s$ p: gThe following are the test combination:
( G8 p! ]8 p+ g6 a1. Power to Power
/ s+ s6 H* M3 |, n1 i  r" V2. Power to Ground3 n3 o0 n$ c/ {* b# p
3. IO to Power
4 M- x5 k" |& p/ w; |. `4. Io to Ground2 s/ d& y  m9 k$ l, r2 S. Y
5. IO to IO% [* g% n4 B7 x* J
(different power domain need to be treated as different power. For ground usually you can treat as one group_silicon use substrate as common ground. But if you measure two different ground pin/ball > 2ohms. It should be seperated as 2 grond.)5 h+ w' u% X6 f4 k3 I; A. @4 |" ^

3 P- c' g: b( r" ~the total zap time fomula will be~ 2(+/- polarity) X (IO#X(P#+G#)+IO#+P#X(P#-1)X(P#-2)X...X1+P#XG)" r+ O8 ~, e6 j3 c/ u$ e+ ]
For example: You have IO1/IO2/IO3/P1/P2/G1) R- Q3 J! [& Y! [' i6 q
2x((3X(2+1)+3+2X1+2X1)=25(multiple the zap interval)2 s: [8 z4 }, [: L
So for high pin count it will take a lot of time. But it won't take more than a week(for one chip). 6 w* e  f7 I! G9 J
0 v( v. T( e( H$ A6 X: p
For your reference.
您需要登錄後才可以回帖 登錄 | 申請會員

本版積分規則

首頁|手機版|Chip123 科技應用創新平台 |新契機國際商機整合股份有限公司

GMT+8, 2024-5-3 02:46 PM , Processed in 0.093005 second(s), 16 queries .

Powered by Discuz! X3.2

© 2001-2013 Comsenz Inc.

快速回復 返回頂部 返回列表